根号下[x^2+(y+4)^2] + 根号下[x^2+(y-4)^2] = 12
人气：377 ℃ 时间：2020-06-12 06:10:05
解答
根号下[x^2+(y+4)^2] + 根号下[x^2+(y-4)^2]= 12√[x^2+(y+4)^2] + √[x^2+(y-4)^2]= 12[x^2+(y+4)^2] + 2√[x^2+(y+4)^2][x^2+(y-4)^2] +[x^2+(y-4)^2]= 144x^2+y^2+8y+16 + 2√[x^2+(y+4)^2][x^...
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