【不好意思,看到题目时太晚了】∠EDC=15°∵AB=AC,AD=AE∴∠B=∠C,∠ADE=∠AED设∠B=∠C=x,∠ADE=∠AED=y∵∠B+∠BAD=∠ADE+∠EDC,∵∠BAD=30°∴ x+30°=y+∠EDC……②∵∠EDC+∠C=∠AED∴x+∠EDC=y∴∠EDC=y-...