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(tan的平方60°cos45°)/(2sin60°-tan45°)+sin30°cos30du°
人气:441 ℃ 时间:2020-02-03 18:02:38
解答
(tan的平方60°cos45°)/(2sin60°-tan45°)+sin30°cos30du°
=(根号3)^2*根号2/2/(2*根号3/2-1)+1/2*根号3/2
=(3/2)根号2/(根号3-1)+根号3/4
=3/2*根号2*(根号3+1)/(3-1)+根号3/4
=3/4*(根号6+根号2)+根号3/4
=3/4根号6+3/4根号2+1/4根号3.
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