设z=a+bi
则(3+2i)(a+bi)=3(a+bi)+3+2i
即(3a-2b)+(2a+3b)i=(3a+3)+(3b+2)i
所以3a-2b=3a+3,2a+3b=3b+2
故a=1,b=-3/2
所以z=1-3i/2