∵p=ρ液gh,
∴ρ液=
p |
gh |
4×102Pa |
10N/kg×4×10−2m |
(2)G金=m金g=0.08kg×10N/kg=0.8N,
F浮=G金-F示=0.8N-0.5N=0.3N,
F浮=G排=m排g,
m排=
F浮 |
g |
0.3N |
10N/kg |
(3)容器对桌面的压力增大值:
△F压=G金-G排=G金-F浮=0.8N-0.3N=0.5N,
容器对桌面的压强增大值:
△P=
△F压 |
S |
0.5N |
50×10−4m2 |
答:(1)液体的密度是1.0×103kg/m3;
(2)金属块排开液体的质量是0.03kg;
(3)容器对桌面的压强增大了100Pa.