KA+B=（k-3,2k+2）,A - 3B=(10,-4)
1.KA+B与A - 3B垂直,得（k-3,2k+2）.(10,-4)＝0
10(k-3)-4(2k+2)=0,解得k=19
2.KA+B与A -3B平行,得
-4(k-3)=10(2k+2),解得k=-1/3