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计算:4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2
人气:157 ℃ 时间:2019-08-22 15:03:37
解答
4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2
=(4xy-x²-2xy-y²)/[xy(x+y)(x-y)]÷[(x-y)(x+2y)]/[xy(x+2y)]
=-(x-y)²/[xy(x+y)(x-y)]÷(x-y)/xy
=-1/(x+y)
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