已知关于x的方程x³-(2m+1)x²+(3m+2)x-m-2=0(1)证明x=1是方程的解(2)把方程左边分成x-1
(2)把方程左边分成x-1与关于x的二次三项式的积的形式
快.马上就要.
人气:298 ℃ 时间:2020-02-06 03:40:55
解答
x³-(2m+1)x²+(3m+2)x-m-2=x³-x²+2x-2-2mx²+3mx-m=x²(x-1)+2(x-1)-m(2x²-3x+1) =x²(x-1)+2(x-1)-m(x-1)(2x-1)=x²(x-1)+2(x-1)-m(x-1)(2x-1)=(x-1)[x²+2-m(2x-1)] ...
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