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m为何正整数时,方程组mx+y+z=0 3mx+(m-1)y+(2m-1)z=0 2mx+3y+(m+3)z=0
人气:174 ℃ 时间:2020-05-20 23:56:32
解答
m = 5,x = -1, y = -6, z = -1----------------令x=-1,则有y + z = m(一式)(m-1)y + (2m-1)z = 3m(二式)3y +(m+3)z = 2m(三式)将一式变形,有z = m-y,带入二式(m-1)y + (2m-1)(m-y) = 3m,整理得y = 2m-4.将z ...
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