∵△ABC是等腰直角三角形∴∠BAC=90°,AB=AC将△APC以A点旋转使AC和AB重合,得△ADB,连接DP∴△APC≌△ADB∴∠CAP=∠BAD,AP=AD=3√2,BD=CP=10∵∠CAP+∠PAB=90°∴∠PAB+∠BAD=90°即∠PAD=90°∴△APD是等腰直角三角...