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求证tan2/x-1/tanx/2=-2/tanx
人气:368 ℃ 时间:2020-05-23 07:37:44
解答
tan(x/2)-1/tan(x/2)=sin(x/2)/cos(x/2)-cos(x/2)/sin(x/2)=sin²(x/2)/sin(x/2)cos(x/2)-cos²(x/2)/sin(x/2)cos(x/2)=[sin²(x/2)-cos²(x/2)]/[sin(x/2)cos(x/2)]=-cosx/[(sinx)/2]=-2/tanx证毕...
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