6-x>0
所以-1
=-log2^(6-x)
=-lg(6-x)/lg2
=lg(6-x)/lg1/2
=log1/2^(6-x)
所以log1/2^(x+1) +log1/2^(6-x)>log1/2^12
log1/2^[(x+1)(6-x)]>log1/2^12
底数1/2<1
所以log1/2^N是减函数
所以(x+1)(6-x)<12
(x-6)(x+1)>-12
x^2-5x+6>0
(x-2)(x-3)>0
x>3,x<2
结合定义域
-1
推荐
- 求不等式log1/2(x+1)≥log2(2x+1)的解集
- 解不等式log1/2(3-x)>=log2(x+3)-1
- 已知x满足不等式?log1/2 x +3≤0求函数f(x)=(log2 x/4)(log2 x/2)的最值
- 已知x满足不等式2(log1/2 x)^2+7log1/2 x+3≤0.f(x)=(log2 x/4)^2(log2 x/2) 求函数的最大值和最小值
- 解不等式log2(x+1)+log1/4(x-1)〉log4(2x-1)
- 七年级地理下册期末试题
- Our homework is always_____.It seems that road is______.It is you who made the surprising___(end)
- 2.Mike often plays () the park ()Sunday afternoon.
猜你喜欢