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分解因式:(1-7t-7t2-3t3)(1-2t-2t2-t3)-(t+1)6=______.
人气:365 ℃ 时间:2019-10-11 04:31:35
解答
设(t+1)3=x,y=t2+t+2,则原式=[2(t2+t+2)-3(1+3t+3t2+t3)][(t2+t+2)-(1+3t+3t2+t3)]-[(t+1)3]2=(2y-3x)(y-x)-x2=2x2-5xy+2y2=(2x-y)(x-2y)=[2(t3+3t2+3t+1)-(t2+t+2)][(t3+3t2+3t+1)-2(...
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