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cos(2π/7)+cos(4π/7)+cos(6π/7)= -1/2.
证明[cos(2π/7)]^2+[cos(4π/7)]^2+[cos(6π/7)]^2=5/4
人气:118 ℃ 时间:2020-07-23 11:26:42
解答
cos(2π/7)+cos(4π/7)+cos(6π/7)= -1/2[cos(2π/7)+cos(4π/7)+cos(6π/7)]^2= 1/4[cos(2π/7)]^2+[cos(4π/7)]^2+[cos(6π/7)]^2+2cos(2π/7)cos(4π/7)+2cos(2π/7)cos(6π/7)+2cos(4π/7)cos(6π/7)=1/4则[cos(...
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