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已知cos(α-π/6)+sinα=4/5 根号3,则sin(α+7/6π)=?
三角函数问题
人气:375 ℃ 时间:2020-01-28 19:51:21
解答
cos(α-π/6)+sinα
=cosα*√3/2+1/2 *sinα+sinα
=cosα*√3/2+3/2 *sinα
=√3(sinπ/6cosα+cosπ/6sinα)
=√3sin(π/6+α)=4/5√3;
sin(α+7π/6)=-sin(α+π/6+π)=-sin(α+π/6)=-4/5
修改了一下楼上的
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