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数学
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y=2sinx/4的最小正周期
y=tan(x/3+π/4)的最小正周期
y=1-sin^2x-cos^2x的最大值
y=1-sinx,x属于[0,π]的值域
人气:366 ℃ 时间:2020-06-07 04:28:01
解答
y=2sinx/4的最小正周期T=2π/(1/4)=8π
y=tan(x/3+π/4)的最小正周期T=π/(1/3)=3π
y=1-sin^2x-cos^2x的最大值
=有误
y=1-sinx,x属于[0,π]的值域
x属于[0,π] sinx属于[0,1]
y=1-sinx,x属于[0,π]的值域 [0,1]
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