{(3-4i)(2+2i)^3}/(4+3i)
=(4-3i)(3-4i)(2+2i)³/25
=-25i(2+2i)³/25
=-(2+2i)³
=-8(1+i)³
=-8(1+3i-3-i）
=-8(-2+2i)
=16-16i