广义积分∫(0~+∞)dx/1+x^2 dx 怎么求?
人气:394 ℃ 时间:2020-05-09 15:20:41
解答
∫(0~+∞)1/(1+x^2) dx
=arctanx [0-->+∞]
=π/2
推荐
猜你喜欢
- 在一根弹簧秤两边各挂一个20N的砝码,为什么弹簧秤示数还是20N
- am,to,going,grandparents,visit,i,my,weekend,this (连词成句)
- some of my students didn't speak english well ,so they had to use ________ to tell foreigner what they wanted to express
- sin(-11/6π)+cos12/5π×tan4π化简
- 最简单的无机化合物是什么?
- 已知,x=2,y=1,为方程组mx-3y=1,nx+2y=8的值,试求3m-5n的值
- 怎么用mathematica 画抛物线和直线的叠加图像?
- ( )1.A:Thanks a lot .B:______ A.That's all right B:That 's right C:All right