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sin^2x+2sinxcosx-3cos^2x=1 求sinx
人气:379 ℃ 时间:2020-03-23 03:45:21
解答
sin^2x+2sinxcosx-3cos^2x=12sinxcosx-4cos^2x=0sinxcosx=2cos^2xcosx(sinx-2cosx)=0(1)cosx=0,sinx=±1(2)sinx=2cosxtanx=2tan^x+1=51/cos^x=5cos^x=1/5sin^x=4/5sinx=±2√5/5
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