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一道微积分题目
求∫(2x+3)/(x^2+2x+2)dx
人气:193 ℃ 时间:2020-03-27 14:30:18
解答
∫(2x+3)/(x^2+2x+2)dx
=∫(2x+2)/(x^2+2x+2)dx+∫1/(x^2+2x+2)dx
=∫d(x^2+2x+2)/(x^2+2x+2)+∫1/[(x+1)^2+1]dx
=ln(x^2+2x+2)+arctan(x+1)+C
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