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已知函数y=3sin(1/2x-π/4)①求此函数的单调增区间.②当x属于【5π/6,17π/6】时函数值域是多少
人气:121 ℃ 时间:2020-06-05 05:38:18
解答
y=3sin(x/2-π/4)
增区间:
x/2-π/4∈[2kπ-π/2.2kπ+π/2]
x∈[4kπ-π/2,4kπ+3π/2]
所以单调增区间为 [4kπ-π/2,4kπ+3π/2]k∈z
x∈[5π/6,17π/6]
x/2-π/4∈[π/6,7π/6]
所以 y的值域为 [-3/2,3]
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