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4a^2b-[3ab^2-(3a^2b-1)],其中a=-0.1,b=1.
人气:263 ℃ 时间:2019-10-19 09:27:01
解答
4a^2b-[3ab^2-(3a^2b-1)]
=4a^2b-3ab^2+(3a^2b-1)
=4a^2b-3ab^2+3a^2b-1
=7a^2b-3ab^2-1
=7×0.01×1-3×(-0.1)×1-1
=0.07+0.3-1
=-0.63
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