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设f(x)=e^3x-1×cos(2πx+π/3),求导数
人气:236 ℃ 时间:2019-08-26 06:52:09
解答
f(x)=e^(3x-1)×cos(2πx+π/3),
f'(x)=e^(3x-1)*(3x-1)'cos(2πx+π/3)-e^(3x-1)*sin(2πx+π/3)*(2πx+π/3)'
=3e^(3x-1)*cos(2πx+π/3)-2π*e^(3x-1)*sin(2πx+π/3)
=e^(3x-1)*[3cos(2πx+π/3)-2π*sin(2πx+π/3)]
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