二进制：1111=1*2^3 +1*2^2+1*2+1*2^0=8+4+2+1=15：十进制
2^3=2的3次方
2^2=2的2次方请给答案在给下详细的过程！求！没听懂你什么意思，猜一下二进制转十进制，比如有n位数,从左到右的值分别乘以2^(n-1)、2^(n-2)、2^(n-3)……2^(n-n)最后相加求和。下面例子：1111111111=1*2^9+1*2^8+1*2^7+1*2^6+1*2^5+1*2^4+1*2^3+1*2^2+1*2+1*2^01010101010=1*2^9+0*2^8+1*2^7+0*2^6+1*2^5+0*2^4+1*2^3+0*2^2+1*2+0*2^01111101010=1*2^9+1*2^8+1*2^7+1*2^6+1*2^5+0*2^4+1*2^3+0*2^2+1*2+0*2^01000001010=1*2^9+0*2^8+0*2^7+0*2^6+0*2^5+0*2^4+1*2^3+0*2^2+1*2+0*2^01010101111=1*2^9+0*2^8+1*2^7+0*2^6+1*2^5+0*2^4+1*2^3+1*2^2+1*2+1*2^0纯手打，满意请赞一个哦