根据勾股定理,AC=BD=
AB2+BC2 |
22+32 |
13 |
∵EF∥AC∥HG,
∴
EF |
AC |
EB |
AB |
∵EH∥BD∥FG,

∴
EH |
BD |
AE |
AB |
∴
EF |
AC |
EH |
BD |
EB |
AB |
AE |
AB |
∴EF+EH=AC=
13 |
∵EF∥HG,EH∥FG,
∴四边形EFGH是平行四边形,
∴四边形EFGH的周长=2(EF+EH)=2
13 |
故选:D.
10 |
13 |
10 |
13 |
AB2+BC2 |
22+32 |
13 |
EF |
AC |
EB |
AB |
EH |
BD |
AE |
AB |
EF |
AC |
EH |
BD |
EB |
AB |
AE |
AB |
13 |
13 |