[（2+2i)/(√3-i)]^7=[(1+i)(√3+i)/2]^7=(√2)^7*[(√2/2+√2/2i)(√3/2+1/2i)]^7=(√2)^7*[(cosπ/4+isinπ/4)(cosπ/6+isinπ/6)]^7=(√2)^7*(cos5π/12+isin5π/12)^7=(√2)^7*(cos35π/12+isin35π/12)=(√2)^7...