1/n(sin0/1 sin1/2 sin2/3 ...sinn-1/n)怎么成∫(01)si
xdx
人气:462 ℃ 时间:2020-09-23 15:27:41
解答
f(x) = sinxdivided (0,1) into n equal intervals with width 1/n0/n ,1/n,2/n,.,(n-1)/n这是定积分的定义(1/n){ sin(0/1)+ sin(1/n)+ sin(2/n)+...+sin[(n-1)/n] }= ∫(0->1) sinx dx
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