令1/[(2-3x)(2x+1)] = M/(2-3x) + N/(2x+1)1 = M(2x+1) + N(2-3x)代x = -1/2,1 = N(7/2) => N = 2/7代x = 2/3,1 = M(7/3) => M = 3/7∴∫ dx/[(2-3x)(2x+1)]= (2/7)∫ dx/(2x+1) + (3/7)∫ dx/(2-3x)= (2/7)(1/2)∫ ...