>
数学
>
∫((3x^4+2x^2)/(x^2+1))dx
人气:378 ℃ 时间:2020-03-22 09:59:28
解答
答:
(3x^4+2x^2)/(x^2+1)
=[3(x^2+1)x^2-(x^2+1)+1]/(x^2+1)
=3x^2-1+1/(x^2+1)
∫((3x^4+2x^2)/(x^2+1))dx
=∫(3x^2-1)dx+∫[1/(x^2+1)]dx
=x^3-x+arctanx+C
推荐
求积分(3x^4+2x^2-x+1/x^2) dx
∫(3x^4+x^2)/(x^2+1)dx
求不定积分 ∫(3x^2-2x+2)dx ∫(2x-1)^2 dx
∫1/[(2-3x)(2x+1)] dx=
∫(3x-2)/(x^2-2x+5)dx
莴苣空心并发黄能吃吗?
当x等于2005时代数式x减1分之x平方减1的值为( )x平方减2y分之3x平方乘以x平方减2xy加y平方分之xy最简公
自行车打气要几个气压
猜你喜欢
2*1+4*3+6*5+8*7+10*9+.+50*49
对闻一多的评价
the risIng sun of (f__) the eastern sky(首字母天空)
You should take some ____ (medicine)
Grow old along with me,the best is yet to be.
点P到圆O的最大距离为20cm,最小距离是10cm,则圆哦的半径是?
计算:2013³-2×2013²-2011/2013³+2013-2014
5.56乘以4减去4.56除以0.25怎么简便运算
© 2024 79432.Com All Rights Reserved.
电脑版
|
手机版