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∫((3x^4+2x^2)/(x^2+1))dx
人气:378 ℃ 时间:2020-03-22 09:59:28
解答
答:
(3x^4+2x^2)/(x^2+1)
=[3(x^2+1)x^2-(x^2+1)+1]/(x^2+1)
=3x^2-1+1/(x^2+1)
∫((3x^4+2x^2)/(x^2+1))dx
=∫(3x^2-1)dx+∫[1/(x^2+1)]dx
=x^3-x+arctanx+C
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