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计算:[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
人气:334 ℃ 时间:2019-11-10 10:09:49
解答
[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2] =(x-1)²/[(x-2)(x+1)]²/(x-1)²/(2-x)/{1/[x²(x+1)²]} =(x-1)²/[(x-2)(x+1)]²/(x-1)²/(2-x)*x²*(x+1)²=-x&s...
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