已知y=2sin(2x+π/6)求:(1)最值及相应的x2x+π/6=2kπ＋π/22x=2kπ＋π/3x=kπ＋π/6取最大值22x+π/6=2kπ＋3π/22x=2kπ＋4π/3x=kπ＋2π/3取最小值-2(2)单调区间递增区间：2kπ-π/2≤2x+π/6≤2kπ＋π/22kπ-...若x∈(﹣π/6,π/2],求值域画出图像（一个周期）