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数学
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lg²2+lg2×lg5+lg²5=?
人气:485 ℃ 时间:2020-05-19 04:00:20
解答
lg2=lg10/5=lg10-lg5=1-lg5
lg²2+lg2×lg5+lg²5
=(1-lg5)²+(1-lg5)×lg5+lg²5
=1-2lg5+lg²5+lg5-lg²5+lg²5
=1-lg5+lg²5
lg²2+2lg2×lg5+lg²5=(lg2+lg5)²=lg²10=1
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