假设直角边为A,B,即A+B+C=1,A*A+B*B=C*C,A=B.所以2A+C=1,2A*A=C*C.2A=1-C所以(1-C)*(1-C)/2=C*C (2C*C-1-C*C+2C)/2=0 C*C-1+2C=0(C+1)(C+1)=2C=根号2-1 2a*a=（根号2-1）*（ 根号2-1 ）面积=a*b/2=a*a/2=（根号2-1）...