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lim(x→0)(x^2)[e^{(1/x^2) }]用洛必达法则求极限
人气:264 ℃ 时间:2020-04-04 04:56:32
解答
令1/x^2=t ,那么t趋于正无穷
lim(x→0)(x^2)[e^{(1/x^2) }]
= lim(t→正无穷)e^t/t (罗比达法则:)
=lim(t→正无穷)e^t
=正无穷
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