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(1)1/a-1/b (2)(x^2+4x+4)/(x^2-4)-x/(x-2) (3)1/b+2/b
人气:464 ℃ 时间:2020-04-04 14:39:56
解答
1/a-1/b=b/ab-a/ab=(b-a)/ab
(x^2+4x+4)/(x^2-4)-x/(x-2)=(x+2)^2/(x+2)(x-2)-x/(x-2)=(x+2)/(x-2)-x/(x-2)=2/(x-2)
1/b+2/b=(1+2)/b=3/b
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