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数学
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1949x(1/51—1/2000)+51X(1/1949—1/2000)—2000X(1/1949+1/51)+3的计算过程.
人气:310 ℃ 时间:2020-04-06 03:41:59
解答
1949x(1/51—1/2000)+51X(1/1949—1/2000)—2000X(1/1949+1/51)+3
=1949/51-1949/2000+51/1949-51/2000-2000/1949-2000/51+3
=(1949-2000)/51+(51-2000)/1949+(-51-1949)/2010+3
=-1-1-1+3
=0
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