y'+p(x)y=q(x)不是有公式吗?y(x)=e^(-∫2xdx)[c+∫2x·e^(∫2xdx)dx]=e^(-x²)[c+∫2x·e^x²dx] =e^(-x²)[c+∫e^x²dx²]=e^(-x²)(c+e^x²)=ce^(-x²)+1