若x^2+x-3=0,则分式3-x^2-x^3/x-1=?
RT
人气：464 ℃ 时间：2020-03-25 02:05:28
解答
x^2+x=3
(3-x^2-x^3)/(x-1)
=[3-(x^2+x^3)]/(x-1)
=[3-x(x+x^2)]/(x-1)
=[3-x*3]/(x-1)
=-3(x-1)/(x-1)
=-3
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