（3x－2）²＋y-3的绝对值＝0,求5（2x-y）-2（6x-2y＋2）＋（4x－3y－½）的值
人气：150 ℃ 时间：2019-09-09 17:21:14
解答
题意得
3x-2=0 y-3=0
∴x=2/3 y=3
∴原式=10x-5y-12x+4y-4+4x-3y-1/2
=2x-4y-4.5
=4/3-12-9/2
=-91/6
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