求极限lim(x趋于1)(x^3-ax^2-x+4)/(x+1)=b
a b为实数
人气:163 ℃ 时间:2020-04-09 19:46:29
解答
应该是趋于-1吧?如果是的话,分母上x^3-ax^2-x+4应该含(x+1)因式x^3+x^2-(a+1)x^2-(a+1)x+(a+2)x+(a+2)+4-(a+2)=(x+1)(x^2-(a+1)x+(a+2))+2-a极限lim(x趋于-1)(x^3-ax^2-x+4)/(x+1)=lim(x趋于-1)((x+1)(x^2-(a+1)x...
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