f(x)=(sinx-1)/根号(3-2cosx-2sinx) =-(1-sinx)/根号[(sin²x-2sinx+1)+(cos²x-2cosx+1)] =-(1-sinx)/根号[(1-sinx)²+(1-cosx)²] =-1/根号[1+(1-cosx)²/(1-sinx)²] 当sinx≠1时 令g(x)...