sundy_333 ,
待定系数法是求这类问题的通法,我再根你进一步,再深入一步,比如说 d/(ax^2+bx+c)如何裂项?d/(ax^2+bx+c)=d/[a(x-x1)(x-x2)]=d/a *{m/(x-x1) +n/(x-x2)} m,n具体是多少,要根据n(x-x1)+m(x-x2)=1来求.