d(∫cost^2dt)/dy*dy/dx-d(∫(√t)sintdt)d(x^2)*d(x^2)/dx +e^x=0cosy^2 * dy/dx-(√x^2)(sinx^2) *2x+e^x=0cosy^2 *y'-2x^2sinx^2+e^x=0y'=(2x^2sinx^2-e^x)/cosy^2我也是这么做的但是答案卫生么等于1/2（y+1/2sin2y）∫<0--y>cost^2dt还是:∫<0--y>cos^2tdt前者那么答案有问题.