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化简根号下(1+cos100°)—根号下(1-cos100°)
人气:459 ℃ 时间:2020-06-10 01:53:55
解答
1+cos100
=1+2cos²50-1
=2cos²50
cos50>0
所以根号下(1+cos100°)
=|√2cos50|
=√2*cos50
1-cos100
=1-(1-2sin²50)
=2sin²50
sin50>0
根号下(1-cos100°)
=|√2sin50|
=√2*sin50
所以原式=√2(cos50-sin50)
=-√2(sin50-cos50)
=-√2[√2sin(50-45)]
=-2sin5
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