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数学
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设 x/y=ln(y/x) ,求 dy/dx
人气:467 ℃ 时间:2020-03-11 20:23:09
解答
x/y=ln(y/x)
x(-1/y^2)y' +1/y = x/y( -y/x^2 +y'/x)
(1/y+x/y^2)y' = 1/y + 1/x
[(y+x)/y^2]y' = (x+y)/xy
y' = y/x
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