已知方程组2x+3y=3a+1,-x-y=a-4的解满足不等式x+2y>1,求a的取值范围
人气:470 ℃ 时间:2020-04-05 03:30:41
解答
由方程组可得x=11-6a y=5a-7
将x y代入不等式x+2y>1得a>1
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