f(x) = 1/（4^x+2)y = f(x+1/2)+n= 1/{4^(x+1/2)+2}+n= 1/{4^x*4^(1/2)+2}+n= 1/(2*4^x+2}+n=g(x)为奇函数则g(-x)=-g(x)：1/{2*4^(-x)+2}+n = -1/(2*4^x+2}-n2n = -1/(2*4^x+2}- 1/{2*4^(-x)+2}= -1/(2*4^x+2}- 4^x/...