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先化简,再求值(3/4a^3+1/2a^3b^3-1/9a^2b^4)/(-1/3ab)^2,其中a=1/2,b=-4 清楚一点
人气:272 ℃ 时间:2019-09-05 07:50:12
解答
(3/4a^3+1/2a^3b^3-1/9a^2b^4)/(-1/3ab)^2
=(a^2/36)(27a+18ab^3-4b^4)/(1/9a^2b^2)
=(27a+18ab^3-4b^4)/4b^2
=27a/4b^2+9ab/2-b^2
=27*(1/2)/4*(-4)^2+9*(1/2)*4/2-(-4)^2
=27/128-7
=-869/128
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