a+b+c=0,(a+1)+(b+2)+(c+3)=6,1/(a+1)+1/(b+2)+1/(c+3)=0,得(b+2)(a+1)+(b+2)(c+3)+(a+1)(c+3)=0（a+1)^2+（b+2)^2+（c+3)^2＝〔(a+1)+(b+2)+(c+3)〕＾2-2〔(b+2)(a+1)+(b+2)(c+3)+(a+1)(c+3)〕＝36