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若a²+2b²-7=0,求:
(1)a²+2b²-3的值 (2)-2a²-4b²+1的值
人气:283 ℃ 时间:2019-11-06 16:26:01
解答
(1)a²+2b²-3 = a²+2b²-7+4 = 0+4 = 4(2)-2a²-4b²+1 = -2(a²+2b²-7)-13 = 0-13 = -13 1)=a²+2b²-3-4+4=(a²+2b²-7)+4=4(2)=-2(a²+2b²)+...
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